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take 240 (look familiar argheyass) and switch the first 2 digits (sound familiar) ;)
good job though

An airplane weighs 10,000 pounds, has a 1000 gallon tank, burns fuel at a rate of 5 gallons per minute, and has a speed in miles per hour of 6,000,000 divided by the sum of weight of the plane and remaining fuel. Each gallon of fuel weighs 10 pounds. With a full tank how far can the plane fly?

(5+X)*(X-5+1)/2

Seloc 10? :)

Right sun.

argheyass cheats!

Total of the 10 dice.

oh now i get Seloc question. I thought it was a trick question since I didn't know dice is a plural term...

"and seloc do you mean the sum of two dice? if its just each individual dice rolled I dont see how you can determine which one, as the probability is = for all 6.."

Archias, the number of possible outcomes are 6^10. The probability of getting a 10 as a sum of all dice is the lowest since all dice need to roll on a 1 to get the sum of 10. So the probability of getting a sum of 10 is 1/(6^10) which is very small chance. now let say the sum is 11. Now one dice out of the 10 dice need to be a 2 while all other being a 1. This mean the probability of getting a sum of 11 is 10/(6^10). The question is to find out what sum have the most probability of getting it. I hope you understand more of this question now :)

well, adding "6" 10 times is 60, and addnig "1" 10 times is 10 (the two sum with the lowest chance)

the average is 70/2 = 35 which was my rough estimate. it serves the purpose of this question, but I did not calculate its actual probability ;o...

edit: oops i was editing some typo here, but i clicked on "REPORT" button on Lord Carnage's post by accident..... sowwiee.....

unless the dice are rigged.

Archias ...The question is to find out what sum have the most probability of getting it. I hope you understand more of this question now :)
yea I just didn't understand what exactly he was asking :) thx

There's no such thing as a 0-sided or 1-sided dice... but I thought that was too trivial to mention.

I haven't yet seen a two sided dice, or a three sided.

Would you like to explain how these would work?

Coins have more than one side 0.o

And those dice are unfair!

or a sphere ;)

yes its 35 probably sun

it has one surface ;p it will always be that one side ;p

but the round one has no edge on the surface :P (of course assuming its perfectly round!)

2x^2-3x-4=0, find x.

It's not imaginary.....just follow through with your working...

The solution is 3+/- sqrt(41) like Sun said and please if you want to post a math problem post an interesting one not these 8th grade run of the mill ones that anybody can do, they should take a bit of thinking.

I'm getting the strange feeling you're doing your homework on our backs.

Only somebody that has these as homework would think they are by any means hard to do.

I just learned that stuff last week.........and yet I can't remember it! I blame this on you!! Ugh, I shouldn't be staying up this late at all.........................

i forgot those classical algebra stuff, learned them in first year. i remember there was exponential representation involved somewhere...

ya i vaguely remember some fundamental formula (i think we even proved it back then..) the exponent moving into the trig argument and stuff. but exatly what it was, i cant remember ;)

but those were easy if u know your stuffs....

:) that refreshed my memory :D

"cant forget about the 4^1/3, raise it to the 12th"

You must be dim, (4^1/3)^12 = 4^(1/3*12)=4^4. Get help kid your situation is dire.