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why dot you show us sun :D

Consider if the ball is partially submerged and when it is totally submerged.

If it is partially submerged, 

If it is totally submerged, 

The radius of the bowl is 15 cm and the ball has radius 5 so points on the sections satisfy the equations:



and



Find for the two separate cases.

For :



For

Here's some new questions that don't require high level of math:

1. Using number from 0-9, each number must be used once. Fill in the blank so that this is true: _*_+_+_+_+_+_+_+_+_ = 100.

(Record the process that you go about to solve this problem. This mean there shouldn't be any random guessing.)

2. Why is the giant hand only 11 inches long?

(This is more of a joke)

3. Show me how you can use three 8s to create a 7.

smart lmao

Correct Lenard.

Although for number 1: You can solve it this way:

X*Y+_+_+_+_+_+_+_+_ = 100

I would like to solve for the first two number using X and Y. The remaining is all the numbers that is not X and Y. We know that all the number added together = 45.

From the above information you can get this: 45 - (X+Y) + (X*Y) = 100.
XY-(X+Y) = 100-45 = 55.

From what I got above, we now know that XY > 55. Now all we need to do is find all pairs of number that satisfy XY > 55.

3 pair exists that match this condition: (7,8), (7,9), (8,9).

Now we must find which one of these three pair match the condition XY - (X+Y) = 55. And (8,9) work perfectly :)

Once upon a time, and old lady went to sell her vast quantity of eggs at the local market.

When asked how many she had, she replied:

Son, I can't count past 100 but I know that.

If you divide the number of eggs by 2 there will be one egg left.
If you divide the number of eggs by 3 there will be one egg left.
If you divide the number of eggs by 4 there will be one egg left.
If you divide the number of eggs by 5 there will be one egg left.
If you divide the number of eggs by 6 there will be one egg left.
If you divide the number of eggs by 7 there will be one egg left.
If you divide the number of eggs by 8 there will be one egg left.
If you divide the number of eggs by 9 there will be one egg left.
If you divide the number of eggs by 10 there will be one egg left.

Finally. If you divide the Number of eggs by 11 there will be NO EGGS left!

How many eggs did the old lady have?

Well done for the above :)

no its not lmao

no my answer is right, but it seem Revenge want to get the smallest number of eggs that satisfy the 10 conditions. To do this you have to go a bit deeper into the math.

Basically to satisfy conditions 1 to 9 it must be divisible by numbers 2 to 10 evenly and add 1 to it. To find the smallest number that satisfy this, you can simply take 2*2*2*3*3*5*7 = 2520. Notice that all number from 2 to 10 can be gotten by multiplying some of the numbers in the set of numbers (2,2,2,3,3,5,7).

We now know that any number times 2520 is all evenly divided by number 2 to 10. Now we need to find a smallest X that satisfy: (2520*X+1) divided 11 evenly. Notice that 2520/11 has a remainder of 1. 2520*2/11 has remainder of 2. 2520*10/11 has remainder of 10. If we add 1 to this, 11 will be evenly divided.

So the smallest number of eggs the lady have is 2520*10+1 = 25,201 eggs.

can we close this thread?  Its making Binh orgasmic.

Claps for binh!

What number comes next in this sequence:

1/1 3/2 7/5 17/12 41/29 ==?==

99/70

The series you wrote are rational approximations of the continued fraction for sqrt(2). The next one in the series is 99/70 and the one after is 239/169.

The bear drowns after chasing a penguin in the sea for 1 hr and eats 0 penguins.

Do I count that as a "probable" event? Sometimes math questions neglect reality and make unnatural assumptions. For example, should we assume the penguins are evenly distributed in the bear's territory, or they are all together at the land next to the sea making it easier for all of them to escape into the water - the latter is closer to reality.

where do you find these answers......

What the heck is sqrt(2)? I thought the answer was that to find the next number, you just double the last number and add the one before it (you do it separately for the numerator and denominator).

As for the other problem, IIII llliiiikkkkkkkeeeeeee ppppeeeennnngggguuuuiiinnnss!

Carnage members may NOT answer as they already have the answer in the forums:

You have 2 coins that add up to $.30 and one of them isn't a nickle, what 2 coins do you have?

The one that isn't a nickel is a quarter, then the other coin is a nickel =)

Edit- I lost =(

"a) (x+4)=0/(5x -10) ----->(Yes I know you can't divide 0 by anything, just assume you can.)"

Actually you can divide 0 by almost anything, it's just 0. As for x, it's -4.

"b) (7x+98)^2=0"

x = -14.

c) 8x+32 = 0 or 2x+20=0
8x = -32 or 2x = -20
x = -4 or x = -10

d) 2x = 0 or 3+6x=0
x = 0 or 6x = -3
x = 0 or x = -1/2

Those were indeed simple.

massive number, really no math I just like this online calculator I have to use
2.14¹⁰²⁶x10<sup>1.7x1028

thats the answer</sup>

3816547290 ??

all you know at first is that #5 is a 5 and 10 is 0 and that the odd digits are in their respective odd positions 3 7 9

good problem :)

#1
Find a 10 digit number such that:
-the first digit tells how many zeros are in the number
-the second digit tells how many ones are in the number
-the third digit tells how many twos are in the number, and so on...
#2
Find the smallest 10 digit number, which uses all the digits (0-9), and is divisible by 1 through 10

just to stay on the 10 digit track :P

1. 9,000,000,000