Forums / Miscellaneous Discussions / Math Tricks/Problems

No, im saying ur equation is wrong

r^b(cos(a*pi)+isin(a*pi))^b = cos(a*b*pi)+isin(a*b*pi).  thats what it should be, but very nice anyways.

P.S. 200th post!

whats, 1+2+3+4+5....etc....999+1000?

The formula is quite simple, it's n(n+1)/2, in our case n=1000 so we have 1000*(1000+1)/2 which is 500500.

seloc, use your head for your homework..

realign 1 to 100 backward, then add it back to the original sequence while paring the smallest to the largest. divide the sum by 2 cuz you added the sequence together twice, and u get the sum....

CHRIST!!!!! $%^$^%%&*^&*!^@#%$%@#&$%

ah right,
yeah i had figured that formula too when i was a child ^^
(1000/2)*1000+500... which is simplified to n(n+1)/2 XD

a real life related problem -

it suddenly started raining outside, and you dont have an umbrella with you. should you run fast to the building, or walk slowly to the building, in order to be the least wet in the process! what do you think is the main factor that will decide how fast you should go.

(this is something i just made up, and i have my own opinionated answer, someone could prove me wrong though)

o didnt watch that on mythbuster.

Assume the rain drop down in a perfect line towards you with a vertical speed (due to gravity and terminal velocity) of A and the horizontal wind is at the speed of B, and I walk at speed of C. Let's say each unit length of rain coming down is also 1 unit in weight for simplicity..... 

Then i take 1/C time to move 1 unit of distance....and you get rain from the top which is constant A, and also rain from the front or back which you run into with absolute value of |B-C|.

So (A+|B-C|) * 1/C give us the simple mass of rain onto you.
(A+B-C)/C=(A+B)/C-1 if B>C>0
Or (A-B+C)/C=(A-B)/C+1 if 0<B<C
Or (A+B+C)/C=(A+B)/C+1 if B<0 but C>0 (opposite direction)

(note that whatever you try to save by the horizontal speed difference always end up as a constant + or - 1)

Now lets assume B>C, so we are running towards the direction of the wind.
Differentiate this with respect to C, we have (A+B)*ln(C) which is always negative, so the original water mass function is a decreasing function.. meaning that C should be super big..... so running is better...? did I make some wrong assumptions or do some incorrect analysis? or over simplification of the problem?.... i am confusing myself now haha!

When they did a simple test on some program on Dutch television (Translated: National Science Quiz) they claimed that it made no difference if you ran or walked.

or you could remember your umbrella next time.

You're just too white and nerdy!
You wanna roll with the gangstas
But so far they all think You're too
White and nerdy...

25%

1/4

GA! 100%, they're in <3 ;)

or 0% cuz <3 is a lie .. like cake :D

This is an interesting thread. Anyhow, in regards to that last one, it depends on whether it is one moment in time or how long, unless they're really slow thinkers. Since you didn't specify a time, they'll be bound to think of each other at some stage at the same time, unless one(or both) die very quickly. Besides that, the two events aren't completely independent, since when they're in the vicinity of each other they'll be more likely to think of each other than when apart. So it would be pretty much 100% - whatever the chance of any given person death is*2 at maybe ten minutes at most.

Finding a calculator, sorry.

364/365 x 363/365 x 362/365 ... 315/365 is the chance of none of them being the same. This is 3%. So the chance that two have the same birthday is 97%.

Doh...

If:


A = A life
B = Nerd
and C = Solving mathematic problems for fun

What is D?

B-A+C=D

D = me!

Not as cool as someone who trolls and makes fun of people in an online war game

To Mr. Homo Ezatous's question.

C = D-B+A, so if you solve math questions for fun:

+A =You have a life

-B = You are not a nerd.

0.012345 %

DID YOU KNOW...

111,111 x 111,111 = 12 345 678 987 654 321

let me make one up.

Betty is a prostitute. who earnt money for her liveing..
Prostitutes make an avarage of 40 dollar/ hour.
with a standard deviation of 10 dollars.
she ows her Pimp 230 Dollars. bye the end of next week. ( she has 7 days)
if she doesnt pay up her pimp will destroy her.
what are the chanses betty will survive??

oops make that 40 dollars a days. she lives in asia..
then itl be 6-8 days that what i meant..